(-3y+3)^2+3y=63

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Solution for (-3y+3)^2+3y=63 equation: 



(-3y+3)^2+3y=63

We move all terms to the left:

(-3y+3)^2+3y-(63)=0

We add all the numbers together, and all the variables

3y+(-3y+3)^2-63=0

We move all terms containing y to the left, all other terms to the right

3y+(-3y+3)^2=63

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